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Start your free trialGilang Ilhami
12,045 PointsLetter game
i'm not sure what's wrong her
when the answer given is 'banana' or 'apple' it doesn't let me win and quit the game
```python import random
make a list of words
words = [ 'apple', 'banana', 'orange', 'strawberry', 'lime', 'grapefruit', 'lemon', 'kumpquat', 'blueberry', 'melon', ]
while True: start = input("Press enter or return, or press Q to quit ") if start.lower() == 'q': break
# pick a random word
secret_word = random.choice(words)
good_guesses = []
bad_guesses = []
while len(bad_guesses) < 7 and len(good_guesses) != len(list(secret_word)):
# draw spaces, guesses letter, and strikes
for letter in secret_word:
if letter in good_guesses:
print(letter, end='')
else:
print ('_', end='')
print ('')
print ("Strikes: {}/7".format(len(bad_guesses)))
print ('')
# take guess
guess = input("Take a guess:").lower()
if len(guess) != 1:
print ("You should answer one letter at a time!")
continue
elif guess in bad_guesses or guess in good_guesses:
print ("You already use that letter")
continue
elif not guess.isalpha():
print ("You can only type letters!")
continue
if guess in secret_word:
good_guesses.append(guess)
if len(good_guesses) == len(list(secret_word)):
print ("You win! The word was {}!".format(secret_word))
break
else:
bad_guesses.append(guess)
else:
print("Sorry you lose... the word was {}".format(secret_word))
1 Answer
Steven Parker
231,269 PointsYou need a different strategy for finding a win.
In the code above, you check the number of correct guesses against the length of the word to determine a win. That will work for words where every letter is different, but for words with repeated letters like 'banana' or 'apple' a win will occur while the number of good guesses is less than the size of the word.
You need a different checking strategy. What if you compared the size of good_guesses against only the number of unique letters, or checked if each letter of the word was in good_guesses?