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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops Refactor Using a Loop

Log an even number from 2 to 24 using loop.

The code below logs all of the even numbers from 2 to 24 to the JavaScript console. However, there's a lot of redundant code here. Re-write this using a loop. I can't get the number 12 on the console log. What am I doing wrong with this challenge?

script.js
for (var i = 2; i < 15; i++){
  console.log(i);
}
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

Use 'let' to remove the scope from global

for ( let i = 2; i <= 24; i += 2) { console.log(i); }

15 Answers

You need to create a for loop that initializes the variable to 2, console.log the variable to the screen, and add two to the variable on each iteration.

Said another way: starting at two, as long as i is less than 25, add two and log the new variable to the screen.

for ( i=2 ; i<25 ; i+=2 ) {
    console.log(i); 
}
Basto Biih
Basto Biih
5,334 Points

Why don't you put in the variable everytime like they do in the videos??

I did this exact code and it didn't work.

Cary Oldenkott
Cary Oldenkott
8,178 Points

Wouldn't

for ( i = 2; i <= 24; i += 2;) { console.log(i); }

work just as well instead of i < 25?

no it's cause you need to add the number 25 like this:

for(i = 2 ; i <= 25 ; i += 2){ console.log(i); }

Jack Cummins
Jack Cummins
17,417 Points

Are you actually sisters?

Chris Drew
Chris Drew
5,919 Points
for (var i = 2; i < 26; i += 2) {
    console.log(i)
}

This works perfectly. Thanks, Chris Drew. Think this particular challenge was a little buggy.

for (i=2; i < 25; i++,i++) { console.log(i); }

for ( i=2 ; i<25 ; i+=2 ) { console.log(i); }

very easy

for ( var i = 2 ; i <= 24 ; i++ ) { if ( i % 2 === 0 ) { console.log (i);

}

}

sorry but this code doesn't work , the right code is like this :

for(i = 2 ; i <= 25; i += 2 ){ console.log(i); }

Thanks a lot.

Sobin Sebastian
Sobin Sebastian
5,348 Points

for ( i = 2; i <= 24; i += 2 ) { console.log ( i ); }

Most of you are correct, but you're missing the let statement for the 'i'.....

for ( let i=2 ; i<25 ; i+=2 ) {
   console.log(i);
}
Abdi Nur
Abdi Nur
3,802 Points

Joseph yours works too, I think the %2 was mentioned in mdn

Million Asseghegn
Million Asseghegn
3,845 Points

var eveni= [1, 2, 3, 4, 5, 6, 8, 9, 10]; for(i=0; i<eveni.length; i+=2){ if(i % 2===0){ console.log("even",i); }}

Diane Bond
Diane Bond
8,011 Points

var number = 0;

do{ number += 2; console.log(number);

}while(number< 24);

Stefan Riley
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Stefan Riley
Front End Web Development Techdegree Graduate 13,099 Points

Hi everyone,

I'm trying to submit this answer and I'm not sure if its being buggy or not. Could someone help me out?

for (i = 2; i <= 24; i += 2) { console.log(i);