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Bami Learn
914 Pointslog method to print out a var
console.log(name);
var name = "Andrew";
var details = { favouriteLanguage: "JavaScript", age: 31, children: 2.4 }
var errorMessage = "Something bad has occurred";
console.log(Andrew);
2 Answers
Ruben Gurdzhian
6,166 PointsYou can't log Andrew, since it is not a variable name. If you would like to log it - you either need to wrap in the the quotes, like this console.log("Andrew") or log a "name" variable value like this console.log(name)
Hope this helps
Bami Learn
914 PointsThanks!
Daniel Botta
17,956 PointsDaniel Botta
17,956 PointsRuben is correct. You are trying to log a string. But in order to do anything with a string in JavaScript, you have to wrap it in single or double quotes. However, as Ruben said, if you want to log the variable called name which stores the string value of "Andrew", you can console.log(name) without any quotes. This is because name = "Andrew";