Logical Operators Challenge

Hi there,

The challenge is looking for something different.

You are looking for all numbers that are divisible by 3 and 7. That is not what the challenge is asking.

It is asking that you find all odd numbers that are divisible by 7.

The code for that looks like this.

var results: [Int] = []

for n in 1...100 {
    // Enter your code below
    if n % 2 != 0 && n % 7 == 0 {
        results.append(n)
    }
    // End code
}

results

I hope that helps,

Mike

PS: Thanks to the awesome resources on Team Treehouse, I just launched my first app. :-)

Code! Learn how to program with Swift

can you break this down step by step I'm completely lost?

I think it's like this

n % 2 compares each of 1...100, which will result in some numbers with a remainder value. != 0 has a remainder that is not 0

n & 7 compares each of 1...100, which will result in some numbers with a remainder value. == 0 has a remainder of 0

&& both conditions apply

results.append(n) This will append the number of numbers found in 1...100 from the task (n) to results