logTeams function

"Is logTeams an anonymous function?"

Yes!

"Are all methods created in an object literal (like Portland) anonymous?"

Not necessarily!

"Or is the key or property name also the name of the function"

No!

JavaScript compilation is a hairy topic that's very easy to get wrong, so I won't pretend to be qualified enough to give you a full answer. I can give you the "What you need to know" version, though.

Functions in JavaScript are objects. They have properties just like any other object you've seen (including those in the referenced video). One such property is name. Essentially, functions with this property set to an empty string are anonymous functions, while those with the property defined are not. Check this out:

function notAnonFunction () {
//...
}
console.log(notAnonFunction.name); //"notAnonFunction"

var someAnonFunction = function() {/*...*/};
console.log(someAnonFunction.name); // ""

var notAnonFunctionExpression = function helloThere() { /*...*/ }; //Variable name has nothing to do with function name
console.log(notAnonFunctionExpression.name); // "helloThere"

// This holds true inside of object literals
var someObject = {
   prop1: function() {/* This is an anonymous function */ }, //Property name has nothing to do with function name
   prop2: function coffeeIsGreat() {/* This is not an anonymous function */}
}

// Named functions can be called recursively
var hero = function zapRowsdower() {
  if(beer) {
    zapRowsdower();
  }
}

Hope this helps!

In the video, logTeams is initially an anonymous function.

logTeams: function() {
  console.log(this.soccerTeams);
}

(05:40) - But later Huston says:

I'm actually going to move my logTeams function down here to its own anonymous function.

And then he writes:

function logTeams () {
  console.log(this.soccerTeams);
}

I thought the above code is a function declaration not an anonymous function???

(06:15) - Or, is Huston referring to the below code as the function expression? Isn't it just a function being assigned as a value in the Portland object?

Portland.foo = logTeams;