Loop issue

Question

Good day

I'm struggling to understand one thing in looping (

See below code:

number_of_attempts = 1

password = input("Password - ") while password != "Wonderbar": if number_of_attempts >= 5: sys.exit("Invalid number of attempts, plesae try again later") password = input("Incorrect password, try again - ") number_of_attempts = number_of_attempts + 1

Can you please explain how the variable (number_of_attempts) is able to obtain a new value based on if the password is incorrect and adds a value to state it must add 1.

The input value of (password) is a string and number_of_attempts is separate variable on it's own that does not call any other values.

I'd understand if the value was was passing through as the variable obtains a new value based on the in example below:

count = 0 while count < 100: print(count) count = count +1

Would really appreciate your feedback.

Answer 1 · 2018-09-19T00:15:02Z

September 19, 2018 12:15am

number_of_attempts = 1

password = input("Password - ")
while password != "Wonderbar":  #While the password entered by the user is NOT 'Wonderbar', do the following:
if number_of_attempts >= 5:  #user has 5 attempts to get his password right
     # If the user has already attempted his password 5 times, don't let him.
     sys.exit("Invalid number of attempts, please try again later") 
#Let the player know his password is incorrect, and let him input again
password = input("Incorrect password, try again - ")
number_of_attempts = number_of_attempts + 1
# add 1 to the number of attempts, AND GO BACK TO CHECK THE WHILE LOOP, to see if the password is 'Wonderbar'

#Once the password is exactly 'Wonderbar', the user may proceed.

Answer 2 · 2018-09-19T00:29:12Z

September 19, 2018 12:29am

# set number_of_attempts to 1
number_of_attempts = 1

# ask user to input password
password = input("Password - ")

# loop while password is not equal to Wonderbar
while password != "Wonderbar": 
    # check if number_of_attempts is greater than or equal to 5
    if number_of_attempts >= 5: 
        # exit with message if above statement is True
        sys.exit("Invalid number of attempts, plesae try again later")
    # ask for password again
    password = input("Incorrect password, try again - ")
    # increment number of attempts by 1
    number_of_attempts = number_of_attempts + 1

The comments should clarify things a little. Also remember that number of attempts is a global variable, it is instantiated outside the loop so is available in the scope of the while loop.

Once the loop runs the first time we go right back to "while password != "Wonderbar" and run the block again. on the second run number_of_attempts = 2, and we repeat until number_of_attempts = 5 then we exit. If the password is correct we exit the loop and the program because there is noting else to run.

Answer 3 · 2018-09-19T00:44:46Z

September 19, 2018 12:44am

Thanks guys.

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Jesse Davidson

Jesse Davidson

Loop issue

See below code:

3 Answers

Marco Cornejo

Marco Cornejo

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Jesse Davidson

Jesse Davidson