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Loop through integers in string and replace with remove

I would like to remove all numbers (Integers) in a string and remove them.

I would like to use

stringByReplacingOccurrencesOfString:@"1" withString:@""];


NSString *myString = @"Hello 1 what 2 is 3 the 4 time5"

will become

NSString *myString = @"Hello what is the time"

1 Answer

There's a couple of way to do this. Using the approach you want, it would look something like this:

myString = [myString stringByReplacingOccurrencesOfString:@"[0-9]" withString:@"" options:NSRegularExpressionSearch range:NSMakeRange(0, myString.length)];

This goes through the entire string looking for the numbers 0 through 9, represented as a regular expression above - [0-9], and deletes them. But, deleting the characters only will leave you with two spaces between each word. If you don't mind that it's ok, but if you do, you have to replace them with a single space:

myString = [myString stringByReplacingOccurrencesOfString:@" " withString:@" "];

This is probably not the cleanest way to remove extra spaces from a string, but it does produce the output you are looking for. I hope it helps.

Excellent. Thank you for your help!