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Noah Harness
1,383 Pointsloop with index
I need to continue through a loop if the 0 index of 'item' is ''a'', otherwise i need to print the item.
HELP PLEASE I think I am really close
def loopy(items):
for item in items:
if item.index(0) = "a":
continue;
else:
print(item)
1 Answer

Umesh Ravji
42,362 PointsHi Noah, you are really close, just small issues with your code.
Comparisons are done with double equals (==
), not using single equals (=
), which are used when assigning values to variables.
Checking if the first character is an a
can be done by checking the character at the first index using the code below:
item[0] == 'a'
Giving you a result of:
def loopy(items):
for item in items:
if item[0] == "a":
continue;
else:
print(item)