make a string into a dictionary

Question

I'm not sure where to go from here, i cant use a for loop right, because it will take each letter into account? not each word?

wordcount.py

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(str):
    str.lower()

Answer 1 · 2018-05-15T16:34:29Z

May 15, 2018 4:34pm

Maybe you could look into .split() function, it separates words from the string.

Answer 2 · 2018-05-15T20:32:38Z

May 15, 2018 8:32pm

try this

example_string = "I do not like it Sam I Am"

def word_count(a):
  # get the string into lower case
  a = a.lower()
  #split the string into a list of words
  list_a = a.split()
  #create an empty dictionary
  dict_a = {}
  #iterate over each item in the list with a for loop
  for i in list_a:
    #count the frequency of each item in the list with the help of count method
    count_i = list_a.count(i)
    #assign the item and its frequency into the empty dictionary as key, value pairs
    dict_a[i] = count_i
  #end the for loop and return the dictionary
  return dict_a


print(word_count(example_string))

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sarvienn thevendran

sarvienn thevendran

make a string into a dictionary

2 Answers

Stanisław Dudzik

Stanisław Dudzik

Mustafa Başaran

Mustafa Başaran