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Python Python Basics (2015) Letter Game App Even or Odd Loop

Tomasz Necek
PLUS
Tomasz Necek
Courses Plus Student 7,028 Points

Make a while loop that runs until start is falsey.

Can anyone explain me what is wrong ? :) Thank you

even.py
import random
start = 5
while True:
  num = random.randint(1, 99)
  def even_odd(num):
       return not num % 2
       print("{} is even".format(num))
  else:
    print("{} is odd")
  start -= 1

5 Answers

Josh Keenan
Josh Keenan
19,652 Points

Change the while condition, to while start does not equal 0!

Josh Keenan
Josh Keenan
19,652 Points

Here is Chris Freeman's solution, this should explain a lot better than I can

Python Python Basics Letter Game App Even or Odd Loop
about 1 month ago by Gerald Wells 4,316
issue on 3rd part of challenge, not sure how to decrement start, also not 100 if my code is correct

Alright, last step but it's a big one.

Make a while loop that runs until start is falsey.

Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99.

If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number.

Finally, decrement start by 1.

I know it's a lot, but I know you can do it!

import random

start = 5

def even_odd(n_num):
    while start == True:
        n_num = random.randint(1,99)
        new_num = n_num % 2
        if new_num != 0:
            print("{} is odd".format(n_num))
        else:
            print("{} is even".format(n_num))
                #return not % 2 ----- not sure what to do with this pre-inserted code
    else:
        start -1

#while loop                                 >>>
#make a random int call 1-99                >>>
#print if number is even/even_odd           >>>
#decrement start by 1

even_odd(n_num)
Add Comment 
2 Answers
2
MOD
Chris Freeman 26,776 about 1 month ago
The intent of the challenge is to used the function even_odd in a while loop:

import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

# Make a while loop that runs until start is falsey.
while start:
    # Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99.
    n_num = random.randint(1,99)
    if even_odd(n_num):
        # If that random number is even (use even_odd to find out)...
        # print "{} is even", putting the random number in the hole. 
        print("{} is even".format(n_num))
    else:
        # Otherwise, print "{} is odd", again using the random number.
        print("{} is odd".format(n_num))
    # Finally, decrement start by 1.
    start -= 1
Tomasz Necek
PLUS
Tomasz Necek
Courses Plus Student 7,028 Points

Still not working. Oops! It looks like Task 1 is no longer passing.

Josh Keenan
Josh Keenan
19,652 Points

Oh yeah the loop should be in the function not the other way around,

Emmanuel Koranteng
Emmanuel Koranteng
21,488 Points

Change while condition to while start != False:

Josh Keenan
Josh Keenan
19,652 Points

In this case this is wrong as the loop won't run still, we do until start is equal to 0 as 0 can also mean false.