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PHP PHP Basics Daily Exercise Program Conditionals

Margaret Koronka
Margaret Koronka
659 Points

Make sure you add the proper spacing, especially near variables.

if ($studentOneGPA == 4.0) { echo $studentOneName . " " . 'made the Honor Roll' ; } else { echo $studentOneName . " " . "has a GPA of" . $studentOneGPA ; }

if ($studentTwoGPA == 4.0) { echo $studentTwoName . " " . 'made the Honor Roll' ; } else { echo $studentTwoName . " " . "has a GPA of" . $studentTwoGPA ; }

index.php
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment
if ($studentOneGPA == 4.0) {
    echo $studentOneName . " " . 'made the Honor Roll' ;
}  else {
    echo $studentOneName . " " . "has a GPA of" . $studentOneGPA ;
}

if ($studentTwoGPA == 4.0) {
    echo $studentTwoName . " " . 'made the Honor Roll' ;
}  else {
    echo $studentTwoName . " " . "has a GPA of" . $studentTwoGPA ;
}

?>

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there, Margaret Koronka! You're very close here. The problem comes into play when the student did not make a 4.0. In this case, Dave made a 3.8. Your code would echo out:

Dave has a GPA of3.8

Instead of:

Dave has a GPA of 3.8

Note the extra space after the word "of".

It's an easy fix, though. In your echo statements for when the student did not make a 4.0, you can include an extra space directly in the string after the word of.

Instead of:

echo $studentTwoName . " " . "has a GPA of" . $studentTwoGPA ;

Try:

// note the space between of and the ending double quotes
echo $studentTwoName . " " . "has a GPA of " . $studentTwoGPA ;

Hope this helps! :sparkles: