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PHP PHP Basics Daily Exercise Program Conditionals

Margaret Koronka
Margaret Koronka
659 Points
Posted by Margaret Koronka
Margaret Koronka
659 Points

Make sure you add the proper spacing, especially near variables.

if ($studentOneGPA == 4.0) { echo $studentOneName . " " . 'made the Honor Roll' ; } else { echo $studentOneName . " " . "has a GPA of" . $studentOneGPA ; }

if ($studentTwoGPA == 4.0) { echo $studentTwoName . " " . 'made the Honor Roll' ; } else { echo $studentTwoName . " " . "has a GPA of" . $studentTwoGPA ; }

index.php 
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment
if ($studentOneGPA == 4.0) {
    echo $studentOneName . " " . 'made the Honor Roll' ;
}  else {
    echo $studentOneName . " " . "has a GPA of" . $studentOneGPA ;
}

if ($studentTwoGPA == 4.0) {
    echo $studentTwoName . " " . 'made the Honor Roll' ;
}  else {
    echo $studentTwoName . " " . "has a GPA of" . $studentTwoGPA ;
}

?>

1 Answer

Jennifer Nordell
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STAFF
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Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there, Margaret Koronka! You're very close here. The problem comes into play when the student did not make a 4.0. In this case, Dave made a 3.8. Your code would echo out:

Dave has a GPA of3.8

Instead of:

Dave has a GPA of 3.8

Note the extra space after the word "of".

It's an easy fix, though. In your echo statements for when the student did not make a 4.0, you can include an extra space directly in the string after the word of.

Instead of:

echo $studentTwoName . " " . "has a GPA of" . $studentTwoGPA ;

Try:

// note the space between of and the ending double quotes
echo $studentTwoName . " " . "has a GPA of " . $studentTwoGPA ;

Hope this helps! :sparkles: