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Margaret Koronka
659 PointsMake sure you add the proper spacing, especially near variables.
if ($studentOneGPA == 4.0) { echo $studentOneName . " " . 'made the Honor Roll' ; } else { echo $studentOneName . " " . "has a GPA of" . $studentOneGPA ; }
if ($studentTwoGPA == 4.0) { echo $studentTwoName . " " . 'made the Honor Roll' ; } else { echo $studentTwoName . " " . "has a GPA of" . $studentTwoGPA ; }
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;
$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;
//Place your code below this comment
if ($studentOneGPA == 4.0) {
echo $studentOneName . " " . 'made the Honor Roll' ;
} else {
echo $studentOneName . " " . "has a GPA of" . $studentOneGPA ;
}
if ($studentTwoGPA == 4.0) {
echo $studentTwoName . " " . 'made the Honor Roll' ;
} else {
echo $studentTwoName . " " . "has a GPA of" . $studentTwoGPA ;
}
?>
1 Answer

Jennifer Nordell
Treehouse TeacherHi there, Margaret Koronka! You're very close here. The problem comes into play when the student did not make a 4.0. In this case, Dave made a 3.8. Your code would echo out:
Dave has a GPA of3.8
Instead of:
Dave has a GPA of 3.8
Note the extra space after the word "of".
It's an easy fix, though. In your echo statements for when the student did not make a 4.0, you can include an extra space directly in the string after the word of.
Instead of:
echo $studentTwoName . " " . "has a GPA of" . $studentTwoGPA ;
Try:
// note the space between of and the ending double quotes
echo $studentTwoName . " " . "has a GPA of " . $studentTwoGPA ;
Hope this helps!