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Gerald Ford
7,104 PointsMake sure your function accepts two parameters, with the correct external and local names
Not working please some help
// Enter your code below
func getRemainder(a value: Int, b divisor: Int) -> Int {
let operation = a % b
return operation
}
2 Answers
James Vlok
17,059 Pointsfunc getRemainder(a value: Int, b divisor: Int) -> Int {
let operation = value % divisor
return operation
}
a and b are the external names for the variable. value and divisor are the names for the variable in the function. eg.. when you call the function you would do the following:
getRemainder(a: 5, b: 10)
hence a and b here are used externally from the function
In the function:
let operation = value % divisor
value and divisor are used.
So in the function you will use value instead of a and divisor instead of b.
value and divisor are just names for the same variable to make the code more readable.
Gerald Ford
7,104 Points// not working func getRemainder(a value: Int, b divisor: Int) -> Int { let operation = value % divisor return operation }
James Vlok
17,059 Pointsfunc getRemainder(value a: Int, divisor b: Int) -> Int{
return a % b
}
This should work. the question states that the external variable names need to be value and divisor. In the function definition just swap value and a , divisor and b
Sorry didn't see that it was apart of a code challenge.
All the best
Gerald Ford
7,104 PointsGerald Ford
7,104 Points//Have tried // Enter your code below func getRemainder(a value: 10 , b divisor: 5) -> 2 { let operation = 10 % 5 return operation } //Then this // Enter your code below func getRemainder(a value: Int, b divisor: Int) -> Int{ let operation = value % divisor return operation } //Before this // Enter your code below func getRemainder(a value: Int, b divisor: Int) -> Int{ let operation = a % b return operation }