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Start your free trialSteve Hunter
57,712 PointsmDeleteButton - set it to the layout button with id 'deleteButton'
I did the following:
public class PhotoFragment extends Fragment {
public Button mDeleteButton;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mDeleteButton = (Button)findViewById(R.id.deleteButton);
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.fragment_photo, container, false);
mDeleteButton = (Button)findViewById(R.id.deleteButton);
return rootView;
}
}
but I am getting compiler errors.
I'm not too sure what I've done wrong. I have moved the line I added around the file but that's not helped.
Any thoughts on what mistake I've made?
Steve.
2 Answers
Paolo Scamardella
24,828 PointsFirst of all you need to get rid of the mDeleteButton = (Button)findViewById(R.id.deleteButton); in the onCreate method. Second, you are dealing with fragments and in your onCreateView method you need to do mDeleteButton = (Button) rootView.findViewById(R.id.deleteButton);
I believe rootView returns your fragment xml layout, and in order to access the button in your fragment layout, you need to use rootView(or whatever variable you give it to).
Hope that helps and make sense!
Steve Hunter
57,712 PointsPerfect - many thanks! :-)
Steve Hunter
57,712 PointsSteve Hunter
57,712 PointsI have only added it once - it's in the onCreate method but I have tried it in the other method too.