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# messy code

since we cant use a string for the key, is this the only way to do the challenge?:

time_machine.py
```import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

def time_machine(integer, string):
if string == 'years':
return starter + datetime.timedelta(days = integer * 365)
elif string == 'days':
return starter + datetime.timedelta(days = integer)
elif string == 'weeks':
return starter + datetime.timedelta(weeks = integer)
elif string == 'seconds':
return starter + datetime.timedelta(seconds = integer)
elif string == 'microseconds':
return starter + datetime.timedelta(microseconds = integer)
elif string == 'milliseconds':
return starter + datetime.timedelta(milliseconds = integer)
elif string == 'minutes':
return starter + datetime.timedelta(minutes = integer)
elif string == 'hours':
return starter + datetime.timedelta(hours = integer)
```

Hi Kevin,

Your code could be about half as short since the challenge states that only "minutes", "hours", "days", or "years" will be passed in.

Beyond that, you could create a dictionary out of the `string`, and `integer` and then unpack the dictionary when you pass it into timedelta. This sets up the proper keyword argument while avoiding the problem of not being able to use a string as the key.

Since "years" is not a valid keyword argument, you first have to check for that and do some adjusting.

```def time_machine(integer, string):
if string == "years":
# if years were passed in then adjust the variables to represent days instead
string = "days"
integer *= 365
return starter + datetime.timedelta(**{string : integer}) # create a dictionary with string and integer and then unpack it
```