Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript Foundations Arrays Methods: Part 2

Posted by Matt James
Matt James
1,948 Points

Methods part 2 - Sort the 'saying2' array, on about line 19, so that the words are listed in length order. The shortest

Getting this error am i misunderstanding the question?? Bummer! The 'saying2' was 'The,quick,brown,fox,jumped,over,the,lazy,dog's,back' not 'The,fox,the,over,lazy,back,quick,brown,dog's,jumped'.

My Code:

  saying2.sort(function(a,b){
    a.length + b.length ;
  });

2 Answers

Matt James
Matt James
1,948 Points
Matt James
Matt James
1,948 Points

this is the full code:

<script>
  var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
  var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
  saying1.reverse();
  saying2.sort(function(a , b){
  return (a - b .length);
  });
</script>
Jason Anello
PLUS
Jason Anello
Courses Plus Student 94,610 Points
Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

You're close in the code you posted as an answer.

Should be return a.length - b.length;

It might be helpful to read about how the compare function works on this mdn page:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort