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JavaScript

Brian Pelowski
Brian Pelowski
7,202 Points
Posted by Brian Pelowski
Brian Pelowski
7,202 Points

Methods Part 3 - Challenge task 1 of 3 On line 18, set the variable 'saying' to the concatenation of the 'first' and 'second' arrays with the word "dog".

I entered the following code: ".concat([second],"dog")"

  var first =  ["The", "quick", "brown", "fox", "jumps"]

  var second =  ["over", "the", "lazy"];

  var saying = first.concat([second],"dog"); 

  var shortSaying = saying;

  var sayingString = saying;

It indicates that I generated the correct code, but apparently the syntax I used was not generated from the syntax that was wanted.

Bummer! Was expecting a 'saying' array of 'The,quick,brown,fox,jumps,over,the,lazy,dog' but got 'The,quick,brown,fox,jumps,over,the,lazy,dog'.

3 Answers

Mike Healy
Mike Healy
2,451 Points
Mike Healy
Mike Healy
2,451 Points

" Was expecting a 'saying' array of 'The,quick,brown,fox,jumps,over,the,lazy,dog' but got 'The,quick,brown,fox,jumps,over,the,lazy,dog'."

Those are the same. Try without [] around second

var saying = first.concat(second,"dog");
Brian Pelowski
Brian Pelowski
7,202 Points
Brian Pelowski
Brian Pelowski
7,202 Points

Hmmmm, I thought I had tried it that way.

But thank you-

Jason Mc Dermott
Jason Mc Dermott
11,496 Points
Jason Mc Dermott
Jason Mc Dermott
11,496 Points

thanks for the help but why aren't [] used for second, if its an array within an array isn't it needed?