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JavaScript

Tyler Lundgren
Tyler Lundgren
6,826 Points
Posted by Tyler Lundgren
Tyler Lundgren
6,826 Points

missing a ) on line three and i cant find where, please help!!!

var guess = 0; function randomNum( lower, upper ) { var guess1 = prompt ("I am thinking of a number between" lower " & " upper " what is it?"); var random = math.floor(math.random() * (upper - lower+ 1)) + lower; return random; guess += 1; if parseInt(guess1) === parseInt(randomNum) { document.write('<p> You guessed it! <p>'); alert("Ok lets do it one more time!"); } else { alert("Try again!"); } }; randomNum( 10, 20 );

Tyler Lundgren
Tyler Lundgren
6,826 Points
Tyler Lundgren
Tyler Lundgren
6,826 Points

not line three, but in the prompt to user... var guess1 = prompt ("i am thinking of a number between" lower "&" upper "what is it?");

1 Answer

Brandon Leichty
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.a{fill-rule:evenodd;}techdegree seal-36
Brandon Leichty
Full Stack JavaScript Techdegree Graduate 35,193 Points
Brandon Leichty
.a{fill-rule:evenodd;}techdegree seal-36
Brandon Leichty
Full Stack JavaScript Techdegree Graduate 35,193 Points

Hey Tyler,

It looks like the error you're you're getting has to do with the string passed into prompt the function. To combine strings with variables, you'll want to use the + operator.

Here's an example: 

var guess1 = prompt ("I am thinking of a number between " + lower + " & " + upper + " what is it?");

Another way you could create the string is by using something called template literals. This is what your same code would look like using template literals: 

var guess1 = prompt (`I am thinking of a number between ${lower} & ${upper} what is it?`);

One other thing I noticed when testing your code is that you'll want to add an opening and closing brace around your if statement, like this:

if (parseInt(guess1) === parseInt(randomNum))

Hope that helps!

-Brandon