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Nathan Keene
7,595 Points`Monster.prototype.takeDamage` is not a function
Getting this whether I have the new property declared or not, even when the method is still on the constructor and the starter code is untouched. Code for the prototype addition:
Monster.prototype.takeDamage = function() { this.health--; };
var Monster = function(name) {
this.name = name;
this.health = 100;
this.takeDamage = function() {
this.health -= 1;
}
};
2 Answers
Bruno Navarrete
Full Stack JavaScript Techdegree Graduate 22,246 PointsThis code should be after your prototype declaration (var Monster...):
Monster.prototype.takeDamage = function() {
this.health -= 1;
}
You'll also have to remove this.takeDamage from the prototype.
Nathan Keene
7,595 PointsBruno, thanks. I swear that's exactly how I had it and it wasn't working before but now it is. I think I might have been leaving out "prototype" from the property assignment in my original code. Either that or it's those damn JavaScript gremlins! :-)
Anyway this works as it should:
function Monster( name ) {
this.name = name;
this.health = 100;
}
Monster.prototype.takeDamage = function() {
this.health--;
};