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JavaScript

Posted by Chris Kwong
Chris Kwong
10,266 Points

More elegant solution using .on('input', function)

Wouldn't:

var $pwInput = $('#password');
$pwInput.on('input', function(){

    if($pwInput.val().length < 8) $(this).next().show();
    else $(this).next().hide();
    console.log();

});

be a more elegant solutions than attaching to the key up event. Since the value would be checked everytime a is pressed even if the user is not entering the form.

1 Answer

mikes02
PLUS
mikes02
Courses Plus Student 16,968 Points
mikes02
mikes02
Courses Plus Student 16,968 Points

Hi Chris,

I think I'd have to agree with you, actually. Keyup will fire on any key regardless of whether or not it changes the input, where the input event only fires when the value of the input has changed. I think keyup was likely used more frequently to support older browsers.