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johnot11
2,315 PointsMust be a bug in this exercise. Arrays console.log.
This code gives an error message. There must be a bug in this exercise. It works fine in my own environment.
var players = ['Jim', 'Shawna', 'Andrew', 'Lora', 'Aimee', 'Nick']; console.log(players[5]);
var players = ['Jim', 'Shawna', 'Andrew', 'Lora', 'Aimee', 'Nick'];
console.log(players[5]);
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
3 Answers
johnot11
2,315 PointsSorry, I noticed it myself after. Sorry. :) Still learning.
Windesson Almeida
Full Stack JavaScript Techdegree Graduate 19,903 Pointsvar players = ['Jim', 'Shawna', 'Andrew', 'Lora', 'Aimee', 'Nick']; console.log(players[0]); console.log(players[5]);
// this is silly. This question should not depend from the last question
anthony amaro
8,686 Pointshello johnot11 as the question says
Now, on the next line, use console.log() again to log out the last item in the array.
it just wants you to console.log() on the next line. i guess you just have to have 2 console.logs