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Python Python Collections (2016, retired 2019) Dictionaries Word Count

andrea kalifa
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.a{fill-rule:evenodd;}techdegree
andrea kalifa
Python Web Development Techdegree Student 2,935 Points
Posted by andrea kalifa
.a{fill-rule:evenodd;}techdegree
andrea kalifa
Python Web Development Techdegree Student 2,935 Points

My challenging code wordcount.py return Bummer, but work fine? What's wrong?

I'm testing and re-testing code, and return always what challenge expect.

I really don't know where am I wrong

Any suggestion? :)

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    while "  " in string:
        string = string.replace("  ", " ")
    string = string.lower().strip().split(" ")
    dic = {}
    for word in string:
        n = 0
        for w in string:
            if word == w:
                n += 1
                dic[word] = n
    return dic

1 Answer

Steven Parker
Steven Parker
229,732 Points
Steven Parker
Steven Parker
229,732 Points

The error message includes this hint: "Be sure you're lowercasing the string and splitting on all whitespace!"

To split on "all whitespace", the argument to "split" should be left empty. Using a space causes it to split explicitly on space characters.