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CSS CSS Basics (2014) Enhancing the Design With CSS Gradients

kabir k
PLUS
kabir k
Courses Plus Student 18,036 Points

My Code Challenge answer is not accepted!

After typing my answer to the Code Challenge, I checked the preview which was fine but the Code Challenge is not accepting my answer. Can someone tell me what I'm doing wrong?

Here's my answer code:

.main-header {
  background-image: linear-gradient(to top, steelblue 0%, darkslateblue 90%);
}
style.css
/* Complete the challenge by writing CSS below */
.main-header {
  background-image: linear-gradient(to top, steelblue 0%, darkslateblue 90%);
}
index.html
<!DOCTYPE html>
<html>
  <head>
    <title>Lake Tahoe</title>
    <link rel="stylesheet" href="page.css">
    <link rel="stylesheet" href="style.css">
  </head>
  <body> 
    <header id="top" class="main-header">
      <span class="title">Journey Through the Sierra Nevada Mountains</span>
      <h1 class="main-heading">Lake Tahoe, California</h1>
    </header>

        <div class="primary-content">
            <p class="intro">
                Lake Tahoe is one of the most breathtaking attractions located in California. It's home to a number of ski resorts, summer outdoor recreation, and tourist attractions. Snow and skiing are a significant part of the area's reputation.
            </p>
            <a class="callout" href="#more">Find out more</a>
        </div><!-- End .primary-content -->
  </body>
</html>

1 Answer

Daniel Johnson
Daniel Johnson
104,132 Points

The steelblue's stop position of 0% is not needed...

style.css
.main-header {
  background-image: linear-gradient(to top, steelblue, darkslateblue 90%);
}
kabir k
kabir k
Courses Plus Student 18,036 Points

Thanks, it worked! But we were thought in the video lesson to include it. How is this one different?

Daniel Johnson
Daniel Johnson
104,132 Points

It's just the default value, so it's not really needed. You can do it either way though, so I think the video and challenge were just not being very clear about what it wanted you to do.