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JavaScript JavaScript Foundations Functions Return Values

My code doesn't seem to work

It seems that my code doesn't work and I have no idea why not. Please help me.

function arrayCounter (array) {
    if (typeof array === "array") {
        return array.length;
    } else {
        return 0
     }
}

3 Answers

Stone Preston
Stone Preston
42,016 Points

have a look at this forum post it will answer some of your questions

Thanks.

<!DOCTYPE html>
<html lang="en">
  <head>
    <title>JavaScript Foundations: Functions</title>
    <style>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
      }
    </style>
  </head>
  <body>
    <h1>JavaScript Foundations</h1>
    <h2>Functions: Return Values</h2>
    <script>

      function arrayCounter (array) {
        if (typeof array === "array") {
          return array.length;
        } else {
          return 0
        }
      }


    </script>
  </body>
</html>
Jason Nelson
Jason Nelson
9,127 Points
function arrayCounter(x){

        if(typeof x == 'undefined'){
          return 0;
        }else if (typeof x == 'string'){
          return 0;
        }else if (typeof x == 'number'){
          return 0;
        }else if (x instanceof Array){
          return x.length;
        }
      }
Jason Nelson
Jason Nelson
9,127 Points

I had an issue with this in a later problem. One solution that was offered was to use "instanceof" instead of typeof.