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JavaScript JavaScript Foundations Functions Return Values

Posted by Unsubscribed User
Unsubscribed User
6,508 Points

My code doesn't seem to work

It seems that my code doesn't work and I have no idea why not. Please help me.

function arrayCounter (array) {
    if (typeof array === "array") {
        return array.length;
    } else {
        return 0
     }
}

3 Answers

Stone Preston
Stone Preston
42,016 Points
Stone Preston
Stone Preston
42,016 Points

have a look at this forum post it will answer some of your questions

Unsubscribed User
Unsubscribed User
6,508 Points

Thanks.

Unsubscribed User
Unsubscribed User
6,508 Points
Unsubscribed User
Unsubscribed User
6,508 Points 
<!DOCTYPE html>
<html lang="en">
  <head>
    <title>JavaScript Foundations: Functions</title>
    <style>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
      }
    </style>
  </head>
  <body>
    <h1>JavaScript Foundations</h1>
    <h2>Functions: Return Values</h2>
    <script>

      function arrayCounter (array) {
        if (typeof array === "array") {
          return array.length;
        } else {
          return 0
        }
      }


    </script>
  </body>
</html>
Jason Nelson
Jason Nelson
9,127 Points
Jason Nelson
Jason Nelson
9,127 Points 
function arrayCounter(x){

        if(typeof x == 'undefined'){
          return 0;
        }else if (typeof x == 'string'){
          return 0;
        }else if (typeof x == 'number'){
          return 0;
        }else if (x instanceof Array){
          return x.length;
        }
      }
Jason Nelson
Jason Nelson
9,127 Points
Jason Nelson
Jason Nelson
9,127 Points

I had an issue with this in a later problem. One solution that was offered was to use "instanceof" instead of typeof.