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Python Python Basics (Retired) Pick a Number! Any Number! The Solution

Iskander Ismagilov
Iskander Ismagilov
13,298 Points

My code for number_game is far cry from Kenneth's. Appreciate for any feedback. And one question if condition.

My:

chance_list = []

import random
random.randint(1, 10)
num = random.randint(1, 10)

def show_help():
    print("Guess a number between 1 to 10. You have 5 chances.")

def output_num(num):
    print(num)

def add_to_list(new_num):
    chance_list.append(new_num)
    print("You used {} chances.".format(len(chance_list)))

show_help()

while True:
    new_num = input(">")
    if len(chance_list) == 5:
        break
    elif int(new_num) == num:
        print("Congratulations!")
        break
    elif int(new_num) > num:
        print("Your number is higher than should be.")
        add_to_list(new_num)
        continue
    elif int(new_num) < num:
        print("Your number is lower than should be.")
        add_to_list(new_num)
        continue

Kenneth's:

import random

rand_num = random.randint(1, 10)
guessed_nums = []
allowed_guesses = 5

while len(guessed_nums) < allowed_guesses:
  guess = input("Guess a number between 1 and 10: ")

  try:
    player_num = int(guess)
  except:
    print("That's not a whole number!")
    break

  if not player_num > 0 or not player_num < 11:
    print("That number isn't between 1 and 10!")
    break

  guessed_nums.append(player_num)

  if player_num == rand_num:
    print("You win! My number was {}.".format(rand_num))
    print("It took you {} tries.".format(len(guessed_nums)))
    break
  else:
    if rand_num > player_num:
      print("Nope! My number is higher than {}. Guess #{}".format(
        player_num, len(guessed_nums)))
    else:
      print("Nope! My number is lower than {}. Guess #{}".format(
          player_num, len(guessed_nums)))
    continue

if not rand_num in guessed_nums:
  print("Sorry! My number was {}.".format(rand_num))

Why doesn't last condition 'if' print out "Sorry! My number was {}.", if a player makes a mistake first time he put in a number? It prints it out after 5 tries done. But his number is already in guessed num list and it's not a rand_num.

if not rand_num in guessed_nums:
  print("Sorry! My number was {}.".format(rand_num))

2 Answers

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points

With 2-space indentation instead of 4-space, it's not as obvious how the code aligns. The final if statement has the same indentation as the while statement. This means the if will not execute until the while has run its course and ended with too many guess or one of the break statements.

Then the if will do a final check to see if the number was guessed (the rand_num is found in the guessed_nums list)