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Gabor Szilagyi
3,283 Pointsmy code is rejected
my code does the job but it gets rejected
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(word):
word = word.lower()
word_list = []
word_list = word.split(" ")
word_collection = []
for word in word_list:
if word not in word_collection:
word_collection.append(word)
word_count = []
for word in word_collection:
word_count.append(word_list.count(word))
return dict(zip(word_collection, word_count))
2 Answers
Christopher Shaw
Python Web Development Techdegree Graduate 58,236 PointsIt is probably your use of split. split(' '), splits on a single white-space, while split() will handle single and multiple white-spaces.
Gabor Szilagyi
3,283 PointsThanks, that did the trick!
Vibhutha Kumarage
3,095 PointsVibhutha Kumarage
3,095 PointsThank you... !!!!