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Start your free trialHARMANDEEP PANNU
2,077 PointsMy code not working
def main():
scores = input("Enter five test scores: ")
scores = [int(x) for x in scores.split(",")]
showLetters(scores)
calc_average(scores)
def showLetters(grades):
for x in grades:
scores = [int(x)]
if x >= 90 and x <= 100:
grades = "A"
elif x >= 80 and x <= 89:
grades = "B"
elif x >= 70 and x <= 79:
grades = "C"
elif x >= 60 and x <= 69:
grades = "D"
elif x < 60:
grades = "F"
print("{:.1f} is {}".format(x, grades))
def calc_average(grades):
total = 0
for el in grades:
scores = [int(el)]
total += el
average = total / 5
letter = showLetters(average)
print("The average is: {:.1f} which is {}".format(average, letter))
main()
line 12, in showLetters
Β Β Β Β for x in grades:
TypeError: 'float' object is not iterable
1 Answer
Steven Parker
231,271 PointsThe wrong argument type is being passed to showLetters().
The function showLetters() takes an iterable argument (such as a list) and prints messages but does not return any value.
But in calc_average() it is being called on this line:
letter = showLetters(average)
The variable average contains a float value at this point, which causes the error. But also notice that letter is being assigned here and will always be None, since showLetters() does not return anything.
HARMANDEEP PANNU
2,077 PointsHARMANDEEP PANNU
2,077 Pointswhen I try
letter = showLetters(average)
It does not print?
Steven Parker
231,271 PointsSteven Parker
231,271 PointsNo, it won't print, instead it causes the error because average is a float value, but the function requires an argument which is iterable (like a list).
It looks like what you want here is a different function, one that would take a single value and return a letter.