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Patrick Stephens
8,237 PointsMy code seems to work perfectly in workspaces when tested, but the challenge says it is returning incorrect values.
My code seems to be accurately returning a list of classes that cover the topics in the given set when run in workspaces, but when run it the challenge it does not pass. What am I missing?
COURSES = {
"Python Basics": {"Python", "functions", "variables",
"booleans", "integers", "floats",
"arrays", "strings", "exceptions",
"conditions", "input", "loops"},
"Java Basics": {"Java", "strings", "variables",
"input", "exceptions", "integers",
"booleans", "loops"},
"PHP Basics": {"PHP", "variables", "conditions",
"integers", "floats", "strings",
"booleans", "HTML"},
"Ruby Basics": {"Ruby", "strings", "floats",
"integers", "conditions",
"functions", "input"}
}
def covers(topics):
courses_covering = []
for course in COURSES:
if topics.issubset(COURSES[course]):
courses_covering.append(course)
return courses_covering
4 Answers

Alexander Davison
65,456 PointsHere's a hint:
You can to use intersection
instead of checking if a set is a sub set
of another.

Patrick Stephens
8,237 PointsOk I may really be missing something, but I get the same error with the following code which uses the difference operator:
def covers(topics): courses = []
for key, value in COURSES.items():
if len(topics - value) == 0:
courses.append(key)
return courses
and I also tried the following function that uses intersection:
def covers(topics): courses = []
for key, value in COURSES.items():
if topics.intersection(value) == topics:
courses.append(key)
return courses
neither of these passed.

implse finite
3,106 PointsHi,
here's my solution, maybe not the best :
def covers(a):
result = []
for k, v in COURSES.items():
b = COURSES[k]
c = a.intersection(b)
if len(c) != 0:
result.append(k)
return result

Patrick Stephens
8,237 PointsThank you everyone for your help. I see my problem now. I was actually solving the next step in the challenge. I thought that every topic in the given set had to be covered in the class, which is not the case. Well, at least I found three different ways to solve the next problem.