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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Stephen Falck
Stephen Falck
7,558 Points
Posted by Stephen Falck
Stephen Falck
7,558 Points

my code works in atom but it keeps saying the output is incorrect on the test

ive tried it repeatedly on atom and the result is correct but here it says: Bummer: Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    dict = {}
    split_string = (string.lower()).split(" ")

    for word in split_string:
        counter = split_string.count(word)
        dict[word] = counter

    return dict

2 Answers

Jennifer Nordell
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STAFF
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Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there, Stephen Falck ! You're doing terrific and you are really close here! I know that when you put in the test data, it looks like you're getting back the correct thing. And that's because you are... for that data. However, the challenge asks you to split on all whitespace. This includes things like tabs and newline characters. But that test data doesn't contain either one of those.

Currently, you are only splitting on spaces, and not other whitespace characters.

This splits on spaces:

split(" ")

But this splits on all whitespace:

split()

Simply removing the argument " " from your split function causes this to pass.

Hope this helps! :sparkles: