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iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

Michael Harris
Michael Harris
1,528 Points

My code works perfectly in the playground. It's not compiling in your editor. I have replaced my print().

My code:

var n = 31 let fizz = "Fizz" let buzz = "Buzz"

if n % 3 == 0 && n % 5 == 0 { print("(fizz)" + "(buzz)") } else if n % 5 == 0 { print(buzz) } else if n % 3 == 0 { print(fizz) } else { print(n) }

I have removed all my variables/constants, added return "FizzBuzz". Still not compiling.

fizzBuzz.swift
func fizzBuzz(n: Int) -> String {

if n % 3 == 0 && n % 5 == 0 {
    return "FizzBuzz"
} else if n % 5 == 0 {
    return "FizzBuzz"
} else if n % 3 == 0 {
    return "FizzBuzz"
} else {
    return "FizzBuzz"
}
  return "\(n)"
}
Michael Harris
Michael Harris
1,528 Points

Nevermind. I took the add return "FizzBuzz" to literally. I added return "Buzz", return "Fizz" etc. and it worked.

1 Answer

Martin Wildfeuer
PLUS
Martin Wildfeuer
Courses Plus Student 11,071 Points

The assignment asks you to return "FizzBuzz", "Buzz" or "Fizz" as a String, instead of printing it to the console. "FizzBuzz" is just one example of a return statement.

Step 3: Change all your print statements to return statements. For example: print("FizzBuzz") becomes return "FizzBuzz".

Therefore, the following should work:

func fizzBuzz(n: Int) -> String {
  if n % 3 == 0 && n % 5 == 0 {
        return "FizzBuzz"
    } else if n % 5 == 0 {
        return "Buzz"
    } else if n % 3 == 0  {
        return "Fizz"
    } else {
        // End code
        return "\(n)"
    }
}

P.S. Code that compiles in a playground has almost certainly no syntax errors, but that does not guarantee the correct result.

Hope that helps :)