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Start your free trialAsher Orr
Python Development Techdegree Graduate 9,410 PointsMy function is not returning the right datetime object- can anyone help me?
Hi everyone!
My function, time_machine, takes an integer and a string of "minutes", "hours", "days", or "years". The parameters describe a timedelta, and I want to return a datetime object that is the timedelta's duration from the starter datetime.
Here's my code:
# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
import datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
def time_machine(int_obj, time_unit):
if time_unit == "minutes":
delta = datetime.timedelta(minutes=int_obj)
if time_unit == "hours":
delta = datetime.timedelta(hours=int_obj)
if time_unit == "days":
delta = datetime.timedelta(days=int_obj)
if time_unit == "years":
delta = datetime.timedelta(days=int_obj/365)
new_obj = starter + delta
return new_obj
I keep getting an error that time_machine doesn't return the right datetime. I would appreciate any insights on why this is occurring.
For what it's worth, I thought it might be an issue with converting the "if time_unit == 'years'" statement. I tried using floor division to see if I could get a more precise number that the checker would accept, like this:
if time_unit == "years":
delta = datetime.timedelta(days=int_obj // 365)
But this hasn't worked either. Thank you for reading!
1 Answer
Mark Sebeck
Treehouse Moderator 38,304 PointsHi Asher. The good news is you are super close. And the issues is not related to your understanding of Python. For years you have -
days=int_obj/365
To set a year you want years * 365.
Asher Orr
Python Development Techdegree Graduate 9,410 PointsAsher Orr
Python Development Techdegree Graduate 9,410 PointsThank you, Mark! I really appreciate it- you cleared up my question perfectly!