Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Christoph Ruepprich
Christoph Ruepprich
2,887 Points

My output is correct, but my answer isn't accepted.

Is there anything I'm doing wrong?

The error is: "Bummer: Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!"

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

starg = "I want the apple the orange the banana"
dictionary = {}

def word_count(string):
    string = string.lower().split(" ")
    for item in string:
        if item in dictionary:
            dictionary[item] = dictionary[item] + 1
            dictionary[item] =  1
    return dictionary

varb = word_count(starg)
print (varb)

1 Answer

Just put the dictionary into the function