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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Christoph Ruepprich
Christoph Ruepprich
2,887 Points

My output is correct, but my answer isn't accepted.

Is there anything I'm doing wrong?

The error is: "Bummer: Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!"

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

starg = "I want the apple the orange the banana"
dictionary = {}


def word_count(string):
    string = string.lower().split(" ")
    for item in string:
        if item in dictionary:
            dictionary[item] = dictionary[item] + 1
        else:
            dictionary[item] =  1
    return dictionary

varb = word_count(starg)
print (varb)

1 Answer

Just put the dictionary into the function