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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Gengjin Wu
Gengjin Wu
7,218 Points

My output match the expected one, but I couldn't pass the quiz

Here is my answer

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(word):
    word = word.lower()
    word_dict = {}
    lists = word.split(" ")
    for each in lists:
        word_dict[each] = lists.count(each)
    return word_dict

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

The error message has a hint: "Bummer: Hmm, didn't get the expected output. Be sure you're lowercasing the string and splitting on all whitespace!"

To split on "all whitespace", leave the argument to "split" empty. If you give it a space it will split only on explicit spaces.