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Start your free trialJose Perez Lopez
9,304 PointsMy program does not run if I print the content, in this case print(html); outside of the for loop.
When I put my function to printout the divs onto the page, my program does not run, however, when I put it inside the for loop, it runs just fine.
var html = ' '; var rgbColor = ''; function getRandomColor(){ return Math.floor(Math.random() * 256); } function color(){ return rgbColor += 'rgb(' + getRandomColor() + ',' + getRandomColor() + ',' + getRandomColor() + ')'; } function printDoc(message){ document.write(message); } for(var i = 0; i < 300; i++){ html += '<div style="background-color:' + color() + '"></div>'; html = ''; rgbColor = ''; } printDoc(html); <<<------ OUTSIDE THE FOR LOOP
This does not run
var html = ' '; var rgbColor = ''; function getRandomColor(){ return Math.floor(Math.random() * 256); } function color(){ return rgbColor += 'rgb(' + getRandomColor() + ',' + getRandomColor() + ',' + getRandomColor() + ')'; } function printDoc(message){ document.write(message); } for(var i = 0; i < 300; i++){ html += '<div style="background-color:' + color() + '"></div>'; printDoc(html); <<------ INSIDE THE FOR LOOP html = ''; rgbColor = ''; } But this does
1 Answer
KRIS NIKOLAISEN
54,972 PointsYou should try console.log(html) just before printDoc(html) to show what you are trying to write. Anyways I modified your color() function to not concatenate rgbColor, and removed html = '' from your loop and it appears to function correctly:
var html = '';
function getRandomColor(){
return Math.floor(Math.random() * 256);
}
function color(){
return 'rgb(' + getRandomColor() + ',' + getRandomColor() + ',' + getRandomColor() + ')';
}
function printDoc(message){
document.write(message);
}
for(var i = 0; i < 300; i++){
html += '<div style="background-color:' + color() + '"></div>';
}
console.log(html)
printDoc(html)