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Amal Shanker
7,200 PointsMy response to Challenge question : string firstName ="Amal"; Shows compiler error
Challenge Task 1 of 3: Define a string variable that specifies your name. I do not understand the meaning of compiler error?? What should be the accurate input?
// I have setup a java.io.Console object for you named console
3 Answers
Julian Garcia
18,380 PointsThe uppercase first letter in string maybe? This works for me:
String firstName="Amal";
Hope this help.
Alexander Kobilinsky
359 Points
John Marley
8,740 PointsA compiler error is returned when there is a mistake in your code and it can not be run. "A compiler is a computer program... that transforms source code written in a programming language (the source language) into another computer language (the target language)... The most common reason for converting source code is to create an executable program. (Wikipedia)
The most likely reason for a compiler error at this stage is your syntax (which is absolutely fine) and your code should be expressed like this.
String myName = "Jeff";
//String is the data type (String being a word or several words, Char being character etc.)
/* myName is the variable name and is usually written with a lower case first letter
and capital for the next word */
//Jeff is the value stored (My name is Jeff)