Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialKeenan Smith
Python Development Techdegree Student 5,487 PointsMy search_challenge function doesn't work
I thought I was adding the function correctly, but im getting a syntax error. Am i missing something else?
from models import Challenge
def create_challenge(name, language, steps=1):
Challenge.create(name=name,
language=language,
steps=steps)
def search_challenges():
challenge = challenge.where(Challenge.content.contains(name, language)
1 Answer
Joseph Yhu
PHP Development Techdegree Graduate 48,638 PointsYour code (for reference):
def search_challenges():
challenge = challenge.where(Challenge.content.contains(name, language)
Two basic things first:
- Your function needs to have two parameters: name and language.
- Your function needs to return a value, which is all
Challenge
s that meet the criteria.
Now for the specifics:
- You don't have to create a variable called
challenge
and assign the results of the query to it; you can just return the query results. - The
c
inchallenge.where
should be capitalized. - You should have a
select()
in betweenChallenge
andwhere
. -
Challenge.name
must contain thename
argument, butChallenge.language
must equal thelanguage
argument.
My solution:
def search_challenges(name, language):
return Challenge.select().where(Challenge.name.contains(name), Challenge.language == language)