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JavaScript JavaScript Numbers Working with Numbers Create a Program with Math

Shawn Butts
Shawn Butts
3,271 Points
Posted by Shawn Butts
Shawn Butts
3,271 Points

My solution to the coding challenge for secondsAlive, I may of taken the "math illiterate" route.

const secsPerMin = 60; const minsPerHour = 60; const hoursPerDay = 24; const daysPerWeek = 7; const weeksPerYear = 52; const year = 365; /* I added this variable */

const secondsPerDay = secsPerMin * minsPerHour * hoursPerDay; console.log(There are ${secondsPerDay} seconds in a day.);

const yearsAlive = 28; let secondsAlive = secondsPerDay * year * yearsAlive; console.log(I've been alive for more than ${secondsAlive} seconds.);

Mark Casavantes
Mark Casavantes
2,880 Points
Mark Casavantes
Mark Casavantes
2,880 Points

Hello Shawn,

On the lines that have "console.log" you need a back tick inside your ().

console.log(`There are ${secondsPerDay} seconds in a day.`);

const yearsAlive = 28;
let secondsAlive = secondsPerDay * year * yearsAlive;
console.log(`I've been alive for more than ${secondsAlive} seconds.`);
Steven Parker
Steven Parker
229,644 Points
Steven Parker
Steven Parker
229,644 Points

The backticks are causing local code quotes since the Markdown formatting isn't being used.

1 Answer

Steven Parker
Steven Parker
229,644 Points
Steven Parker
Steven Parker
229,644 Points

When posting code, always use Markdown formatting to preserve the code's appearance and retain special symbols. With the formatting, it looks like this:

const secsPerMin = 60;
const minsPerHour = 60;
const hoursPerDay = 24;
const daysPerWeek = 7;
const weeksPerYear = 52;
const year = 365; /* I added this variable */

const secondsPerDay = secsPerMin * minsPerHour * hoursPerDay;
console.log(`There are ${secondsPerDay} seconds in a day.`);

const yearsAlive = 28;
let secondsAlive = secondsPerDay * year * yearsAlive;
console.log(`I've been alive for more than ${secondsAlive} seconds.`);

While this solution works, it doesn't make use of the defined constants for daysPerWeek and weeksPerYear. You might try using them in the calculation instead of creating another constant (though I must admit, your strategy yields a slightly more accurate value :wink:).