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JavaScript AJAX Basics (retiring) jQuery and AJAX Stage 3 Challenge

My solution using $.ajax()

  type: 'json',
  method: 'GET',
  success: (rooms) => {
    let html = '<ul class="rooms">';
    let $div = $('#roomList'); 
    $.each(rooms,(index,room) => {
      let roomNum = room.room;
      let isAvailable = room.available ? 'empty' : 'full';
      html += `<li class="${isAvailable}">${roomNum}</li>`;
    html += '</ul>';
  error: (jqXHR) => {
    let $div = $('#roomList'); 
    $div.html(`<p>Error: ${jqXHR.status} - File: ${jqXHR.statusText}!</p>`);
Petar Karagenov
Petar Karagenov
8,608 Points

Why are you using //type : 'json'// ? In the documentary for the $.ajax method it said that //type// is "An alias for method. You should use type if you're using versions of jQuery prior to 1.9.0." So I think it really should be //type: 'GET'//.

Ruben Dario Avila Home
Ruben Dario Avila Home
8,806 Points

Hey but I can't use your form:

<li class="${isAvailable}">${roomNum}</li>

and I change to:

'<li class="' + isAvailable + '">' + roomNum + ' </li>';

Why you use the ${isAvailable}, ${roomNum} any documentation of this?

2 Answers

Ruben Dario Avila Home
Ruben Dario Avila Home
8,806 Points

Really Nice Solution, elegant and refined! Soo Cool! Good job :)

Michael Moore
Michael Moore
7,121 Points

I learned things about javascript from your answer, lol. Nice answer, really.