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JavaScript JavaScript Foundations Variables Shadowing

Posted by Lorenas Bartkus
Lorenas Bartkus
14,593 Points

myFunc variable scope global vs inside function

When I execute following code (Chrome and Firefox) and I still get variable myColor value set to yellow. Am I doing something wrong? Code: 

    <// Shadowing
    <var myColor = "blue";
    <console.log("myColor before myFunc", myColor);
    <
    <function myFunc() {
<  myColor = "yellow";
<  console.log("My color inside myFunc", myColor);
    <}

    <myFunc();
    <console.log("myColor after myFunc()", myColor);

Console output: <myColor before myFunc blue myscript.js:62 <My color inside myFunc yellow myscript.js:66 <myColor after myFunc() yellow myscript.js:70

2 Answers

Lorenas Bartkus
Lorenas Bartkus
14,593 Points
Lorenas Bartkus
Lorenas Bartkus
14,593 Points

Sorry my mistake I forgot to use var declaring variable myColor inside the function.

Benjamin Gooch
Benjamin Gooch
20,367 Points
Benjamin Gooch
Benjamin Gooch
20,367 Points

I did the same thing and I'm glad you figured out your mistake! If you hadn't, I'd still be trying to figure it out. JS is way more complex than CSS or HTML, as I am learning.