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Reed Mangino
1,621 PointsMySQL: Stage 7 Calculating...
The question asks:
Like before, group reviews by "movie_id", get the average "score" as "average" and filter out any averages over 2.
My answer is:
select avg(score) as average from reviews group by movie_id having average > 2;
which is flagged as incorrect.
If I type it into MySQL Workbench it works as expected.
Does anyone see the problem? Thanks!
2 Answers
Fraser Boag
6,381 PointsIf i'm not mistaken, your query would only display reviews which have a score greater than 2 - whereas the question asks for these to be filtered out (ie only display results with an average of less than or equal to 2). I think this may be the problem, however I'm not very familiar with HAVING so I am guessing a bit at its usage (based on my understanding of WHERE).
Reed Mangino
1,621 PointsThat was my problem - thanks!