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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

'name' error

You've used the string .format() method before to fill in blank placeholders. If you give the placeholder a name, though, like in template below, you fill it in through keyword arguments to .format(), like this: template.format(name="Kenneth", food="tacos") Write a function named string_factory that accepts a list of dictionaries as an argument. Return a new list of strings made by using ** for each dictionary in the list and the template string provided.

# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(name= None, food= None):
    if name and food:
        return ",".join(template.format(name, food))

string_factory(**{"name" :"Kenneth", "food" : "tacos"})

1 Answer

Ismail KOÇ
Ismail KOÇ
1,748 Points

Before the define this function, you neeed to add values dictionary for ex:

template = "Hi, I'm {name} and I love to eat {food}!"
values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garlield", "food": "Lasagna"}]

after define values, define function it needs to include values

Write a function named string_factory that accepts a list of dictionaries as an argument. and we will unpack dictionary for return values

def string_factory(values):
    return [template.format(**x) for x in values]

here python tekes values as argument, doing for loop for get value items (keys and values), then unpacking value of values dictionary with x and return a new list (using .format() method) if you want to how **return included for loop, check out this tutorial