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Python

Posted by Iskander Ismagilov
Iskander Ismagilov
13,298 Points

NameError: Try and except

def game():
  try:
    new = int(input())
  except ValueError:
      print("{} isn't int".format(new))
      game()

game()

When I run this script and inputing a string or float, it gives me: "UnboundLocalError: local variable 'new' referenced before assignment"

Wasn't assignment before referencing as an input?

And how to print the wrong input without an error?

1 Answer

Alfonso Concha
Alfonso Concha
3,773 Points

When you use Try and Except, if the Try block result in an exception the code inside it wont get executed and instead the Except block gets executed. So in the script you have, when you dont provide a valid Int for new, that code doesnt get executed so the Print call inside the Except block doesnt know what New is, and it gets a UnboundLocalError. You should save the input as a string and then have a Try and Except block.

Iskander Ismagilov
Iskander Ismagilov
13,298 Points

Thank you!