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JavaScript AJAX Basics (retiring) Programming AJAX Processing JSON Data

Posted by OLUBUKOLA OGUNSOLA
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OLUBUKOLA OGUNSOLA
Full Stack JavaScript Techdegree Graduate 30,442 Points

NaN

MY code is not working , all Inget is NaN.

1 Answer

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

NaN stands for Not a Number. Maybe there's a problem with arithmetic or numbers in your code.

The only way I can help is by looking at your code. Please provide your code.

OLUBUKOLA OGUNSOLA
.a{fill-rule:evenodd;}techdegree seal-36
OLUBUKOLA OGUNSOLA
Full Stack JavaScript Techdegree Graduate 30,442 Points

var xhr = new XMLHttpRequest(); xhr.onreadystatechange = function () { if(xhr.readyState === 4) { var employees = JSON.parse(xhr.responseText); var statusHTML = '<ul class="bulleted">'; for (var i=0; i<employees.length;i++){ if(employees[i].inoffice === true) { statusHTML += '<li class= "in">'; } else { statusHTML += '<li class= "out">'; }

  statusHTML += employees[i].name;
  statusHTML =+ "</li>";
}
  statusHTML += '</ul>';
document.getElementById("employeeList").innerHTML = statusHTML;

} };

xhr.open('GET', 'data/employees.json'); xhr.send();