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Start your free trialDavid Chacón
1,086 PointsNeed a helping hand/shove on step 4/5 of teachers.py
Hey community! I've been getting GREAT help so far but alas, my python logic and knowledge is a little stumped.
Not sure what I'm doing or not doing correct. I know it is in the 'if' statement but can't figure it out. Help would be great, not direct answers please!
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(teachers):
count = 0
for teacher in teachers:
count += 1
return count
def num_courses(courses):
count = 0
for i in courses:
count += len(courses[i])
return count
def courses(courses):
count = []
for i in courses:
count += courses[i]
return count
def most_courses(teacher):
leader = 0
teacherMost = ""
for i in teacher:
if i in teacher[i] > leader:
leader = len(teacher[i])
teacherMost = teacher.value()
else:
continue
return teacherMost
2 Answers
Kurt Maurer
16,725 PointsHey David,
Great job so far. In your for loop, i
is referencing the key in the dictionary.
def most_courses(teacher):
leader = 0
teacherMost = ""
for i in teacher:
# if i in teacher[i] > leader:
if len(teacher[i]) > leader:
leader = len(teacher[i])
teacherMost = i # Since i is the key, don't need teacher.value()
else:
continue
return teacherMost
Also, another way to do it:
def most_courses(teacher):
leader = 0
teacherMost = ""
for key, value in teacher.items():
if len(value) > leader:
leader = len(value)
teacherMost = key
else:
continue
return teacherMost
Both passed the challenge, hope this helps!
Matthew Gilbert
9,817 PointsI keep getting this Error: Bummer: Didn't get the right teacher name!
Kurt Maurer
16,725 PointsKurt Maurer
16,725 PointsAlso worth noting:
This is implicit and not required for your code to work. You can delete it if you want.