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Python Python Collections (2016, retired 2019) Lists Disemvowel

Mobe AF
Mobe AF
3,040 Points
Posted by Mobe AF
Mobe AF
3,040 Points

Need advice !

Hello ,

Now i am stuck in this challenge and i dont know what i am doing wrong , its says that it didn't get back the right answer . from the output i see that some letters are removed but others not .

disemvowel.py 
def disemvowel(word):
    word1 = list(word)
    vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
    for letter in vowels:
        if letter in word1:
            word1.remove(letter)
    word2 = "".join(word1)


    return word2

3 Answers

Jakob Hansen
Jakob Hansen
13,746 Points
Jakob Hansen
Jakob Hansen
13,746 Points

If we assume your word is: ('eKAAeiRJcJ') we expect to get back KRJcJ, but with your code we get KAeRJcJ. as soon as your code has removed the first incident of a vowel, it no longer checks against that vowel.

You need to check for multiple cases of the same vowel as well :)

A hint, is an if statement the best approach inside the for loop :)?

think about this; as long as "this vowel" is inside the word list -> remove it)

Daniel Marin
Daniel Marin
8,021 Points
Daniel Marin
Daniel Marin
8,021 Points

Hi Mobe AF , Here's what I did for that test:

def disemvowel(word):
    vowels = "aeiou"
    result = list()

    for letter in word:
        if letter.lower() not in vowels:
            result.append(letter)

    return ''.join(result)

We do a foreach on letters from the word and then we check if the letter is lower and is not a vowel then we append the letter to result.

Also there's another short way. I had to edit this :)

def disemvowel(word):
    return "".join(c for c in word if c.lower() not in 'aeiou')
Mobe AF
Mobe AF
3,040 Points
Mobe AF
Mobe AF
3,040 Points

passed it , thank you guys so much , really appreciated.