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Python Django Basics Model Administration First app view

Abe Daniels
PLUS
Abe Daniels
Courses Plus Student 2,781 Points
Posted by Abe Daniels
Abe Daniels
Courses Plus Student 2,781 Points

Need an extra set of eyes to look this over.

I am trying to create a new view and the error I am getting back is kinda vague.

Can someone be my bug splatter?

articles/views.py 
#Now, create a view named article_list that selects all Article instances and returns an HttpResponse like "There are 5 articles." 
#Be sure to use the len() of the Article queryset to get the number of articles.

from django.http import HttpResponse

from .models import Article

def article_list(request):
    s = Article.objects.all()
    output = 'There are ' + len(s) + ' articles'
    return HttpResponse(output)

3 Answers

Ryan Clodfelter
Ryan Clodfelter
10,247 Points

Django is probably complaining because you are trying to implicitly cast an int as a string.

You can use .format to fix your issue like so...

from django.http import HttpResponse

# Write your views here
from .models import Article

def article_list(request):
  s = Article.objects.all()
  output = 'There are {} articles'.format(len(s))
  return HttpResponse(output)
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

Correct, if updated with Ben Ackles comment below: "missing a period (.)"

oxanaox
oxanaox
16,295 Points
oxanaox
oxanaox
16,295 Points

Ryan, your solution does not work. Any ideas?

Ben Ackles
Ben Ackles
27,551 Points
Ben Ackles
Ben Ackles
27,551 Points

Ryan's solution works fine. The only problem is the string is missing a period (.) at the end. It's supposed to read "There are 5 articles."