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Start your free trialAlejandro Byrne
2,562 PointsNeed answer with explanation.. been stuck on this challenge for a few days..
Ok, could someone please tell me how to solve this? I think I'm pretty close. sorry to bug you...
def disemvowel(word):
word = list(word)
vowels = ['a', 'A', 'e', 'E', 'u', 'U', 'i', 'I', 'o', 'O']
for item in word:
if item in vowels:
word.remove(item)
else:
continue
return word
3 Answers
Alexander Davison
65,469 Pointsdef disemvowel(word):
result = []
for letter in word:
if letter.lower() not in 'aeiou':
result.append(letter)
return ''.join(result)
Step-by-step Explanation:
- We define the function
- We create an empty list containing no elements
- We go through every letter in the passed-in argument
- If the letter we're currently on lowercased isn't in 'aeiou'... (yes, you can check and see if a string is inside another string)
- (If the letter we are on isn't a vowel...) We add the letter to the
reuslt
list. - Finally, we join together the list by using
''.join(result)
and returning it. Think of''.join(result)
asresult.join('')
. It makes a little more sense that way, but remember that isn't valid Python!
I hope this helps
~Alex
Alejandro Byrne
2,562 PointsAlright, thanks. It worked. Sorry for all the ruckus, I have to learn more about the .join method and checking wether a list/string is in another string/list.
slavster
1,551 PointsAlexander Davison I really like your method of dealing with capitals. I was trying to write 2 For loops using the .lower() and .upper() function to handle both kinds. Your approach of looking at the word object, comparing all the letters in a single case, but then outputting the original case is much quicker. Very clever!
Steven Parker
231,269 PointsNever try to modify an item within a loop that is iterating that same item.
It will cause your loop to skip over some of the items. So instead, use a copy of the item to control the loop. An easy way to make a copy is using a slice with empty arguments.
Also, remember to convert your list back into a string before you return it!
Alejandro Byrne
2,562 PointsHow's this?
def disemvowel(word):
word = []
vowels = ['a', 'A', 'e', 'E', 'u', 'U', 'i', 'I', 'o', 'O']
for item in word:
if item in vowels:
continue
else:
word.append(item)
word = str(word)
return word
[MOD: added ```python formatting -cf]
Chris Freeman
Treehouse Moderator 68,441 PointsExactly! By adding slice notations [:] a copy is made for the iterable which is then protected from changes to the actual value of word
:
for item in word[:]:
Steven Parker
231,269 PointsAlmost....
Applying my suggestions to your original code would give you this (and pass the challenge):
def disemvowel(word):
word = list(word)
vowels = ['a', 'A', 'e', 'E', 'u', 'U', 'i', 'I', 'o', 'O']
for item in word[:]: # loop using copy
if item in vowels:
word.remove(item)
else:
continue
return ''.join(word) # convert list back to string
But just for fun, Python also makes it possible to do essentially the same job in a single line:
def disemvowel(word):
return ''.join([letter for letter in word if letter.lower() not in 'aeiou'])
Modou Sawo
13,141 PointsHi Alejandro,
1) Try putting your vowels variable outside the function.
2) Inside the function, assign an empty list to a variable (i.e. output) 3) Create a for loop, like so:
for letter in list(word):
if not letter.lower() in vowels:
output += letter
output = ''.join(output)
return output
Like Steven said - you have to convert output list into a string.
Alejandro Byrne
2,562 PointsHmmmm... I'm sorry. I don't understand what to do, what changes do I make to the original function? I don't understand the code you gave me. Sorry for being so stubborn.
Alexander Davison
65,469 PointsAlexander Davison
65,469 PointsTagging Chris Freeman