Java Java Basics Getting Started with Java Strings, Variables, and Formatting

need help

Now replace <YOUR NAME> in the console.printf expression with the firstName variable using the string formatter.

Name.java
// I have setup a java.io.Console object for you named console
String firstName = "kishor";
console.printf("kishor can code in java");
consloe.printf("%s can code in java", firstname);

2 Answers

Sean M
MOD
Sean M
Treehouse Moderator 6,447 Points

You accidentally mistyped firstName. You just need to make sure to use camel case for referencing in Java. It should be:

console.printf("%s can code in java", firstName);

Hope that helped.

bot .net
bot .net
11,911 Points

Hi! you have a 2 typos in your code, instead of "console" you typed consloe:

consloe.printf("%s can code in java", firstname);

and instead of firstName, you typed "firstname", u dont refer to ur firstName var and because of that u cant get the name.

consloe.printf("%s can code in java", firstname);

the correct code look like this:

String firstName = "kishor";
console.printf("kishor can code in java");
console.printf("%s can code in java", firstName);

if this answer helped mark this answer as best answer

farai ted mandoreba
farai ted mandoreba
10,767 Points

thanks guys you are very helpful it helped