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Python Python Collections (Retired) Dictionaries Word Count

Need help adding keys and values to dict.

I'm getting (Bummer! 'if' ) from the challenge when I check work. I don't know what is wrong. If anyone can help that would be awesome. Thanks!

word_count.py
my_dict = {}

def word_count(a):

    x = a.lower()
    y = x.split(' ')

    for word in y:
        if word in x:
            my_dict[word] += 1
        else:
            my_dict[word] = 1

    return my_dict




# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.

1 Answer

Sorry I figured out that I needed to change

if word in x:     #  to
if word in my_dict:

thank and I hope if anyone else has a problem this will help them.

[MOD added formatting -cf]