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Python Python Basics (2015) Letter Game App Even or Odd Loop

Need help on the following question

Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

even.py
import random
start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    num = random.randin(1,99)
    dundun = even_odd(num)
    if dundun:
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start = start - 1

1 Answer