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iOS Closures in Swift 2 Building Standard Library Functions Using Filter

Posted by Sam Murphy
Sam Murphy
10,469 Points

Need help on the Using Filters code challenge

my code is raising an error " Make sure you're assigning the results of the filter operation to a constant named oddNumbers" but i don't understand what i am doing wrong. Please help thanks!

filter.swift 
let numbers = [10,423,802,765,943,12,405,230,1348,128,237].filter { $0 % 2 != 0 }
let oddValues = numbers.filter

2 Answers

David Papandrew
David Papandrew
8,386 Points
David Papandrew
David Papandrew
8,386 Points

Sam, the closure needs to follow the numbers.filter call when you declare the oddValues constant.

Here's how the code should look:

let numbers = [10,423,802,765,943,12,405,230,1348,128,237]
let oddValues = numbers.filter { $0 % 2 != 0 }
Jhoan Arango
Jhoan Arango
14,575 Points
Jhoan Arango
Jhoan Arango
14,575 Points

Hello Sam:

There are two ways of doing it. 

// 1 )

let numbers = [10,423,802,765,943,12,405,230,1348,128,237].filter { $0 % 2 != 0 }
let oddValues = numbers

// 2 ) 

let numbers = [10,423,802,765,943,12,405,230,1348,128,237]
let oddValues = numbers.filter { $0 % 2 != 0 }

You were doing it right, but when you were assigning "numbers" to the "oddValues" constant, you were calling the filter closure again.

Good luck